What are the solutions to the equation 4x^2+25x+8=0 ?

The solutions to the equation 4x^2+25x+8=0 are x=(-25+sqrt(497))/8 ,x=(-25-sqrt(497))/8

Find the zeros of 4x^2+25x+8=0

The zeros of 4x^2+25x+8=0 are x=(-25+sqrt(497))/8 ,x=(-25-sqrt(497))/8

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4 x^{2} + 25 x + 8 = 0

x = \frac{- 25 + 497}{8}, x = \frac{- 25 - 497}{8}

Decimal Notation

x = - 0.33831 \dots, x = - 5.91168 \dots

Solution steps

4 x^{2} + 25 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 4 \cdot 8}{2 \cdot 4}

2 5^{2} - 4 \cdot 4 \cdot 8 = 497

x_{1, 2} = \frac{- 25 \pm 497}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 25 + 497}{2 \cdot 4}, x_{2} = \frac{- 25 - 497}{2 \cdot 4}

x = \frac{- 25 + 497}{2 \cdot 4} : \frac{- 25 + 497}{8}

x = \frac{- 25 - 497}{2 \cdot 4} : \frac{- 25 - 497}{8}

The solutions to the quadratic equation are:

x = \frac{- 25 + 497}{8}, x = \frac{- 25 - 497}{8}

x \cdot 2 x = 4 \cdot 13

x^{2} + 1 = 0

(2 x + 3) (x + 4) = 67

v^{2} = - v + 30

4 m^{2} - 6 m - 14 = 10

What are the solutions to the equation 4x^2+25x+8=0 ?
The solutions to the equation 4x^2+25x+8=0 are x=(-25+sqrt(497))/8 ,x=(-25-sqrt(497))/8
Find the zeros of 4x^2+25x+8=0
The zeros of 4x^2+25x+8=0 are x=(-25+sqrt(497))/8 ,x=(-25-sqrt(497))/8