What are the solutions to the equation x^2+5x^2=-4 ?

The solutions to the equation x^2+5x^2=-4 are x=sqrt(2/3)i,x=-sqrt(2/3)i

Find the zeros of x^2+5x^2=-4

The zeros of x^2+5x^2=-4 are x=sqrt(2/3)i,x=-sqrt(2/3)i

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x^{2} + 5 x^{2} = - 4

x = \frac{2}{3} i, x = - \frac{2}{3} i

Solution steps

x^{2} + 5 x^{2} = - 4

Add similar elements:

x^{2} + 5 x^{2} = 6 x^{2}

6 x^{2} = - 4

Divide both sides by

6

x^{2} = - \frac{2}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{2}{3}, x = - - \frac{2}{3}

- \frac{2}{3} = \frac{2}{3} i

- - \frac{2}{3} = - \frac{2}{3} i

x = \frac{2}{3} i, x = - \frac{2}{3} i

(12 t^{2} - 10 t + 5) + (10 t - 15) = 0

x, x^{2} + x y = 20 x

x, x^{2} + x y = 20 y

x = y^{2}, y

x^{2} + x + 10 = 20

What are the solutions to the equation x^2+5x^2=-4 ?
The solutions to the equation x^2+5x^2=-4 are x=sqrt(2/3)i,x=-sqrt(2/3)i
Find the zeros of x^2+5x^2=-4
The zeros of x^2+5x^2=-4 are x=sqrt(2/3)i,x=-sqrt(2/3)i