What are the solutions to the equation (t-5)^2-1/4 =0 ?

The solutions to the equation (t-5)^2-1/4 =0 are t= 11/2 ,t= 9/2

Find the zeros of (t-5)^2-1/4 =0

The zeros of (t-5)^2-1/4 =0 are t= 11/2 ,t= 9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(t - 5)^{2} - \frac{1}{4} = 0

t = \frac{11}{2}, t = \frac{9}{2}

Decimal Notation

t = 5.5, t = 4.5

Solution steps

(t - 5)^{2} - \frac{1}{4} = 0

Move

\frac{1}{4}

to the right side

(t - 5)^{2} = \frac{1}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

t - 5 = \frac{1}{4} : t = \frac{11}{2}

Solve

t - 5 = - \frac{1}{4} : t = \frac{9}{2}

The solutions to the quadratic equation are:

t = \frac{11}{2}, t = \frac{9}{2}

(4 x + 2)^{2} = 4

x^{2} + (x + 2)^{2} = 290

(3 x - 2)^{2} - (2 x - 1)^{2} = 7

x^{2} + (x + 2)^{2} = 381

\frac{y ^{2}}{2} = 1

What are the solutions to the equation (t-5)^2-1/4 =0 ?
The solutions to the equation (t-5)^2-1/4 =0 are t= 11/2 ,t= 9/2
Find the zeros of (t-5)^2-1/4 =0
The zeros of (t-5)^2-1/4 =0 are t= 11/2 ,t= 9/2