What are the solutions to the equation (x+2)^2=27 ?

The solutions to the equation (x+2)^2=27 are x=3sqrt(3)-2,x=-3sqrt(3)-2

Find the zeros of (x+2)^2=27

The zeros of (x+2)^2=27 are x=3sqrt(3)-2,x=-3sqrt(3)-2

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(x + 2)^{2} = 27

x = 33 - 2, x = - 33 - 2

Decimal Notation

x = 3.19615 \dots, x = - 7.19615 \dots

Solution steps

(x + 2)^{2} = 27

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 27 : x = 33 - 2

Solve

x + 2 = - 27 : x = - 33 - 2

The solutions to the quadratic equation are:

x = 33 - 2, x = - 33 - 2

3 x^{2} = (8 + 4 x) (x - 2)

3 (4 x - 1)^{2} + 1 = - 16

- 0.5 x^{2} + 3.2 x - 2 = 0

3 x^{2} - 16 x

3 x^{2} - 15 x

What are the solutions to the equation (x+2)^2=27 ?
The solutions to the equation (x+2)^2=27 are x=3sqrt(3)-2,x=-3sqrt(3)-2
Find the zeros of (x+2)^2=27
The zeros of (x+2)^2=27 are x=3sqrt(3)-2,x=-3sqrt(3)-2