What are the solutions to the equation 5y^2=29 ?

The solutions to the equation 5y^2=29 are y=sqrt(29/5),y=-sqrt(29/5)

Find the zeros of 5y^2=29

The zeros of 5y^2=29 are y=sqrt(29/5),y=-sqrt(29/5)

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5 y^{2} = 29

y = \frac{29}{5}, y = - \frac{29}{5}

Decimal Notation

y = 2.40831 \dots, y = - 2.40831 \dots

Solution steps

5 y^{2} = 29

Divide both sides by

5

y^{2} = \frac{29}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{29}{5}, y = - \frac{29}{5}

x^{2} = 20 - 8 x

x^{2} = 140

(b - 2)^{2} - 3 = 0

x^{2} = 153

1 m^{2} = 81

What are the solutions to the equation 5y^2=29 ?
The solutions to the equation 5y^2=29 are y=sqrt(29/5),y=-sqrt(29/5)
Find the zeros of 5y^2=29
The zeros of 5y^2=29 are y=sqrt(29/5),y=-sqrt(29/5)