What are the solutions to the equation 6x^2=-5+11x ?

The solutions to the equation 6x^2=-5+11x are x=1,x= 5/6

Find the zeros of 6x^2=-5+11x

The zeros of 6x^2=-5+11x are x=1,x= 5/6

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6 x^{2} = - 5 + 11 x

x = 1, x = \frac{5}{6}

Decimal Notation

x = 1, x = 0.83333 \dots

Solution steps

6 x^{2} = - 5 + 11 x

Move

11 x

to the left side

6 x^{2} - 11 x = - 5

Move

5

to the left side

6 x^{2} - 11 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 6 \cdot 5}{2 \cdot 6}

(- 11)^{2} - 4 \cdot 6 \cdot 5 = 1

x_{1, 2} = \frac{- ( - 11 ) \pm 1}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 1}{2 \cdot 6}, x_{2} = \frac{- ( - 11 ) - 1}{2 \cdot 6}

x = \frac{- ( - 11 ) + 1}{2 \cdot 6} : 1

x = \frac{- ( - 11 ) - 1}{2 \cdot 6} : \frac{5}{6}

The solutions to the quadratic equation are:

x = 1, x = \frac{5}{6}

p^{2} + 7 p + 2 = 0

3 x^{2} - 17 x = - 10

(x - 5)^{2} = 18

15 x^{2} + 840 x - 3600 = 0

3 b^{2} - 31 b + 56 = 0

What are the solutions to the equation 6x^2=-5+11x ?
The solutions to the equation 6x^2=-5+11x are x=1,x= 5/6
Find the zeros of 6x^2=-5+11x
The zeros of 6x^2=-5+11x are x=1,x= 5/6