What are the solutions to the equation 5u^2+u=4 ?

The solutions to the equation 5u^2+u=4 are u= 4/5 ,u=-1

Find the zeros of 5u^2+u=4

The zeros of 5u^2+u=4 are u= 4/5 ,u=-1

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5 u^{2} + u = 4

u = \frac{4}{5}, u = - 1

Decimal Notation

u = 0.8, u = - 1

Solution steps

5 u^{2} + u = 4

Move

4

to the left side

5 u^{2} + u - 4 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 4 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 4) = 9

u_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 5}

Separate the solutions

u_{1} = \frac{- 1 + 9}{2 \cdot 5}, u_{2} = \frac{- 1 - 9}{2 \cdot 5}

u = \frac{- 1 + 9}{2 \cdot 5} : \frac{4}{5}

u = \frac{- 1 - 9}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

u = \frac{4}{5}, u = - 1

z^{2} + 6 z = r^{2} - 9

X^{2} = 4^{2} + 1 6^{2}

s^{2} - 14 s + 53

2 X (X - 1) = 4 X - 3

5 x^{2} - 9 = 4 x

What are the solutions to the equation 5u^2+u=4 ?
The solutions to the equation 5u^2+u=4 are u= 4/5 ,u=-1
Find the zeros of 5u^2+u=4
The zeros of 5u^2+u=4 are u= 4/5 ,u=-1