What are the solutions to the equation 7y+3y^2=20 ?

The solutions to the equation 7y+3y^2=20 are y= 5/3 ,y=-4

Find the zeros of 7y+3y^2=20

The zeros of 7y+3y^2=20 are y= 5/3 ,y=-4

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7 y + 3 y^{2} = 20

y = \frac{5}{3}, y = - 4

Decimal Notation

y = 1.66666 \dots, y = - 4

Solution steps

7 y + 3 y^{2} = 20

Move

20

to the left side

7 y + 3 y^{2} - 20 = 0

Write in the standard form

a x^{2} + b x + c = 0

3 y^{2} + 7 y - 20 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 20 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 20) = 17

y_{1, 2} = \frac{- 7 \pm 17}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- 7 + 17}{2 \cdot 3}, y_{2} = \frac{- 7 - 17}{2 \cdot 3}

y = \frac{- 7 + 17}{2 \cdot 3} : \frac{5}{3}

y = \frac{- 7 - 17}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

y = \frac{5}{3}, y = - 4

- 29 = 4 z - 17 z^{2} + 13 z^{2}

49 s^{2} + 70 s = - 25

2 x^{2} - 30 x + 100 = 0

x^{2} - 75 x + 20 = 0

2 (x - 4) (x - 8) = - 1

What are the solutions to the equation 7y+3y^2=20 ?
The solutions to the equation 7y+3y^2=20 are y= 5/3 ,y=-4
Find the zeros of 7y+3y^2=20
The zeros of 7y+3y^2=20 are y= 5/3 ,y=-4