What are the solutions to the equation 5y^2+1=8 ?

The solutions to the equation 5y^2+1=8 are y=sqrt(7/5),y=-sqrt(7/5)

Find the zeros of 5y^2+1=8

The zeros of 5y^2+1=8 are y=sqrt(7/5),y=-sqrt(7/5)

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5 y^{2} + 1 = 8

y = \frac{7}{5}, y = - \frac{7}{5}

Decimal Notation

y = 1.18321 \dots, y = - 1.18321 \dots

Solution steps

5 y^{2} + 1 = 8

Move

1

to the right side

5 y^{2} = 7

Divide both sides by

5

y^{2} = \frac{7}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{7}{5}, y = - \frac{7}{5}

3 (3 x - 2) = (x - 4) (x + 4)

4 B = (t + 2)^{2}

6 a^{2} - 2 = 0

x, g = a (x - h)^{2} + 3

\frac{3}{2} x^{2} = x + 4

What are the solutions to the equation 5y^2+1=8 ?
The solutions to the equation 5y^2+1=8 are y=sqrt(7/5),y=-sqrt(7/5)
Find the zeros of 5y^2+1=8
The zeros of 5y^2+1=8 are y=sqrt(7/5),y=-sqrt(7/5)