What are the solutions to the equation 9x^2+8x-5=0 ?

The solutions to the equation 9x^2+8x-5=0 are x=(-4+sqrt(61))/9 ,x=-(4+sqrt(61))/9

Find the zeros of 9x^2+8x-5=0

The zeros of 9x^2+8x-5=0 are x=(-4+sqrt(61))/9 ,x=-(4+sqrt(61))/9

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9 x^{2} + 8 x - 5 = 0

x = \frac{- 4 + 61}{9}, x = - \frac{4 + 61}{9}

Decimal Notation

x = 0.42336 \dots, x = - 1.31224 \dots

Solution steps

9 x^{2} + 8 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 9 ( - 5 )}{2 \cdot 9}

8^{2} - 4 \cdot 9 (- 5) = 261

x_{1, 2} = \frac{- 8 \pm 2 61}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 8 + 2 61}{2 \cdot 9}, x_{2} = \frac{- 8 - 2 61}{2 \cdot 9}

x = \frac{- 8 + 2 61}{2 \cdot 9} : \frac{- 4 + 61}{9}

x = \frac{- 8 - 2 61}{2 \cdot 9} : - \frac{4 + 61}{9}

The solutions to the quadratic equation are:

x = \frac{- 4 + 61}{9}, x = - \frac{4 + 61}{9}

(x - 4)^{2} - 144 = 0

- X^{2} + 5 X - 100 = 0

x^{2} + 15 x + 18 = 0

(x - 2)^{2} + (1 - 3 x)^{2} = 5

x^{2} + 12 x + 36 = 121

What are the solutions to the equation 9x^2+8x-5=0 ?
The solutions to the equation 9x^2+8x-5=0 are x=(-4+sqrt(61))/9 ,x=-(4+sqrt(61))/9
Find the zeros of 9x^2+8x-5=0
The zeros of 9x^2+8x-5=0 are x=(-4+sqrt(61))/9 ,x=-(4+sqrt(61))/9