What are the solutions to the equation (y-7)^2-6(y-7)+5=0 ?

The solutions to the equation (y-7)^2-6(y-7)+5=0 are y=12,y=8

Find the zeros of (y-7)^2-6(y-7)+5=0

The zeros of (y-7)^2-6(y-7)+5=0 are y=12,y=8

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(y - 7)^{2} - 6 (y - 7) + 5 = 0

y = 12, y = 8

Solution steps

(y - 7)^{2} - 6 (y - 7) + 5 = 0

Expand

(y - 7)^{2} - 6 (y - 7) + 5 : y^{2} - 20 y + 96

y^{2} - 20 y + 96 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 96}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 96 = 4

y_{1, 2} = \frac{- ( - 20 ) \pm 4}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 20 ) + 4}{2 \cdot 1}, y_{2} = \frac{- ( - 20 ) - 4}{2 \cdot 1}

y = \frac{- ( - 20 ) + 4}{2 \cdot 1} : 12

y = \frac{- ( - 20 ) - 4}{2 \cdot 1} : 8

The solutions to the quadratic equation are:

y = 12, y = 8

59 = y^{2} - 10 y

p^{2} - 5 p - 24 = 0

8 x = 9 - x^{2}

x^{2} - 11 x + 27 = 3

y^{2} + 4 y - 1 = 0

What are the solutions to the equation (y-7)^2-6(y-7)+5=0 ?
The solutions to the equation (y-7)^2-6(y-7)+5=0 are y=12,y=8
Find the zeros of (y-7)^2-6(y-7)+5=0
The zeros of (y-7)^2-6(y-7)+5=0 are y=12,y=8