What are the solutions to the equation 24x^2-82x+63=0 ?

The solutions to the equation 24x^2-82x+63=0 are x= 9/4 ,x= 7/6

Find the zeros of 24x^2-82x+63=0

The zeros of 24x^2-82x+63=0 are x= 9/4 ,x= 7/6

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24 x^{2} - 82 x + 63 = 0

x = \frac{9}{4}, x = \frac{7}{6}

Decimal Notation

x = 2.25, x = 1.16666 \dots

Solution steps

24 x^{2} - 82 x + 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 82 ) \pm ( - 82 ) ^{2} - 4 \cdot 24 \cdot 63}{2 \cdot 24}

(- 82)^{2} - 4 \cdot 24 \cdot 63 = 26

x_{1, 2} = \frac{- ( - 82 ) \pm 26}{2 \cdot 24}

Separate the solutions

x_{1} = \frac{- ( - 82 ) + 26}{2 \cdot 24}, x_{2} = \frac{- ( - 82 ) - 26}{2 \cdot 24}

x = \frac{- ( - 82 ) + 26}{2 \cdot 24} : \frac{9}{4}

x = \frac{- ( - 82 ) - 26}{2 \cdot 24} : \frac{7}{6}

The solutions to the quadratic equation are:

x = \frac{9}{4}, x = \frac{7}{6}

2 x^{2} + 21 x - 36 = 0

3 t^{2} - 5 t = 1

5 x^{2} = 3 x - 4

x^{2} + (- \frac{3}{6})^{2} = 1

5 x^{2} = 3 x + 8

What are the solutions to the equation 24x^2-82x+63=0 ?
The solutions to the equation 24x^2-82x+63=0 are x= 9/4 ,x= 7/6
Find the zeros of 24x^2-82x+63=0
The zeros of 24x^2-82x+63=0 are x= 9/4 ,x= 7/6