What are the solutions to the equation 3x^2-x=x^2-4x ?

The solutions to the equation 3x^2-x=x^2-4x are x=0,x=-3/2

Find the zeros of 3x^2-x=x^2-4x

The zeros of 3x^2-x=x^2-4x are x=0,x=-3/2

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3 x^{2} - x = x^{2} - 4 x

x = 0, x = - \frac{3}{2}

Decimal Notation

x = 0, x = - 1.5

Solution steps

3 x^{2} - x = x^{2} - 4 x

Move

4 x

to the left side

3 x^{2} + 3 x = x^{2}

Move

x^{2}

to the left side

2 x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

3^{2} - 4 \cdot 2 \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 \cdot 2}, x_{2} = \frac{- 3 - 3}{2 \cdot 2}

x = \frac{- 3 + 3}{2 \cdot 2} : 0

x = \frac{- 3 - 3}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{3}{2}

27 x^{2} = 27

3 (x - 6) = 5 x^{2} + 1

x^{2} - 7 x = - 12

3 x^{2} + 5 x - 28 = 0

- 15 x^{2} - 3.139 x + 11.25 = 0

What are the solutions to the equation 3x^2-x=x^2-4x ?
The solutions to the equation 3x^2-x=x^2-4x are x=0,x=-3/2
Find the zeros of 3x^2-x=x^2-4x
The zeros of 3x^2-x=x^2-4x are x=0,x=-3/2