What are the solutions to the equation 0=-x^2+3x+28 ?

The solutions to the equation 0=-x^2+3x+28 are x=-4,x=7

Find the zeros of 0=-x^2+3x+28

The zeros of 0=-x^2+3x+28 are x=-4,x=7

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0 = - x^{2} + 3 x + 28

x = - 4, x = 7

Solution steps

0 = - x^{2} + 3 x + 28

Switch sides

- x^{2} + 3 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 28}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 28 = 11

x_{1, 2} = \frac{- 3 \pm 11}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 11}{2 ( - 1 )}, x_{2} = \frac{- 3 - 11}{2 ( - 1 )}

x = \frac{- 3 + 11}{2 ( - 1 )} : - 4

x = \frac{- 3 - 11}{2 ( - 1 )} : 7

The solutions to the quadratic equation are:

x = - 4, x = 7

x^{2} - x = \frac{1}{3}

x^{2} + 2 x + 7 = 15

x, 0 = - 0.02 x^{2} + x + 2.6

(2 x - 7)^{2} + 3 = 52

3 x^{2} - 5 x = 2 x + 6

What are the solutions to the equation 0=-x^2+3x+28 ?
The solutions to the equation 0=-x^2+3x+28 are x=-4,x=7
Find the zeros of 0=-x^2+3x+28
The zeros of 0=-x^2+3x+28 are x=-4,x=7