What are the solutions to the equation (2x-7)^2+3=52 ?

The solutions to the equation (2x-7)^2+3=52 are x=7,x=0

Find the zeros of (2x-7)^2+3=52

The zeros of (2x-7)^2+3=52 are x=7,x=0

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(2 x - 7)^{2} + 3 = 52

x = 7, x = 0

Solution steps

(2 x - 7)^{2} + 3 = 52

Move

3

to the right side

(2 x - 7)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 7 = 49 : x = 7

Solve

2 x - 7 = - 49 : x = 0

The solutions to the quadratic equation are:

x = 7, x = 0

3 x^{2} - 5 x = 2 x + 6

5 x^{2} - 8 x + 10 = 0

4 - 6 x^{2} = 10

7^{2} + c^{2} = 2 5^{2}

y^{2} - 10 y = - 16

What are the solutions to the equation (2x-7)^2+3=52 ?
The solutions to the equation (2x-7)^2+3=52 are x=7,x=0
Find the zeros of (2x-7)^2+3=52
The zeros of (2x-7)^2+3=52 are x=7,x=0