What are the solutions to the equation 10^2+11^2=c^2 ?

The solutions to the equation 10^2+11^2=c^2 are c=sqrt(221),c=-sqrt(221)

Find the zeros of 10^2+11^2=c^2

The zeros of 10^2+11^2=c^2 are c=sqrt(221),c=-sqrt(221)

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1 0^{2} + 1 1^{2} = c^{2}

c = 221, c = - 221

Decimal Notation

c = 14.86606 \dots, c = - 14.86606 \dots

Solution steps

1 0^{2} + 1 1^{2} = c^{2}

Switch sides

c^{2} = 1 0^{2} + 1 1^{2}

Simplify

1 0^{2} + 1 1^{2} : 221

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 221, c = - 221

λ^{2} - 4 λ + 4 = 0

x^{2} + 9 x - 1620 = 0

x^{2} - 5 x + 2 = 8

x, 11 x^{2} + 12 x - 11 = 0

23 = x^{2} - 4 x + 2

What are the solutions to the equation 10^2+11^2=c^2 ?
The solutions to the equation 10^2+11^2=c^2 are c=sqrt(221),c=-sqrt(221)
Find the zeros of 10^2+11^2=c^2
The zeros of 10^2+11^2=c^2 are c=sqrt(221),c=-sqrt(221)