What are the solutions to the equation 1/3 (2x+3)^2=2 ?

The solutions to the equation 1/3 (2x+3)^2=2 are x=(sqrt(6)-3)/2 ,x=(-sqrt(6)-3)/2

Find the zeros of 1/3 (2x+3)^2=2

The zeros of 1/3 (2x+3)^2=2 are x=(sqrt(6)-3)/2 ,x=(-sqrt(6)-3)/2

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\frac{1}{3} (2 x + 3)^{2} = 2

x = \frac{6 - 3}{2}, x = \frac{- 6 - 3}{2}

Decimal Notation

x = - 0.27525 \dots, x = - 2.72474 \dots

Solution steps

\frac{1}{3} (2 x + 3)^{2} = 2

Multiply both sides by

3

(2 x + 3)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 3 = 6 : x = \frac{6 - 3}{2}

Solve

2 x + 3 = - 6 : x = \frac{- 6 - 3}{2}

The solutions to the quadratic equation are:

x = \frac{6 - 3}{2}, x = \frac{- 6 - 3}{2}

x^{2} + x \cdot 0 + 0^{2} = 7

2 x^{2} - 5 x = 88

64 x^{2} + 80 x + 16 = 0

\frac{x}{3} (x + 5) = 0

618 = 232 x + 4.9 x^{2}

What are the solutions to the equation 1/3 (2x+3)^2=2 ?
The solutions to the equation 1/3 (2x+3)^2=2 are x=(sqrt(6)-3)/2 ,x=(-sqrt(6)-3)/2
Find the zeros of 1/3 (2x+3)^2=2
The zeros of 1/3 (2x+3)^2=2 are x=(sqrt(6)-3)/2 ,x=(-sqrt(6)-3)/2