What are the solutions to the equation -2x^2+240x-5500=0 ?

The solutions to the equation -2x^2+240x-5500=0 are x=5(12-sqrt(34)),x=5(12+sqrt(34))

Find the zeros of -2x^2+240x-5500=0

The zeros of -2x^2+240x-5500=0 are x=5(12-sqrt(34)),x=5(12+sqrt(34))

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- 2 x^{2} + 240 x - 5500 = 0

x = 5 (12 - 34), x = 5 (12 + 34)

Decimal Notation

x = 30.84524 \dots, x = 89.15475 \dots

Solution steps

- 2 x^{2} + 240 x - 5500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 240 \pm 24 0 ^{2} - 4 ( - 2 ) ( - 5500 )}{2 ( - 2 )}

24 0^{2} - 4 (- 2) (- 5500) = 2034

x_{1, 2} = \frac{- 240 \pm 20 34}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 240 + 20 34}{2 ( - 2 )}, x_{2} = \frac{- 240 - 20 34}{2 ( - 2 )}

x = \frac{- 240 + 20 34}{2 ( - 2 )} : 5 (12 - 34)

x = \frac{- 240 - 20 34}{2 ( - 2 )} : 5 (12 + 34)

The solutions to the quadratic equation are:

x = 5 (12 - 34), x = 5 (12 + 34)

(x + 13)^{2} = 21

x, (x - 1)^{2} = 9

x, f (x - 3) = 4 x^{2} - 5 x

b, a (a + b) (a + b + c) = 11

2 d^{2} + 5 d - 12 = 0

What are the solutions to the equation -2x^2+240x-5500=0 ?
The solutions to the equation -2x^2+240x-5500=0 are x=5(12-sqrt(34)),x=5(12+sqrt(34))
Find the zeros of -2x^2+240x-5500=0
The zeros of -2x^2+240x-5500=0 are x=5(12-sqrt(34)),x=5(12+sqrt(34))