What are the solutions to the equation 3(x+4)^2-81=0 ?

The solutions to the equation 3(x+4)^2-81=0 are x=3sqrt(3)-4,x=-3sqrt(3)-4

Find the zeros of 3(x+4)^2-81=0

The zeros of 3(x+4)^2-81=0 are x=3sqrt(3)-4,x=-3sqrt(3)-4

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3 (x + 4)^{2} - 81 = 0

x = 33 - 4, x = - 33 - 4

Decimal Notation

x = 1.19615 \dots, x = - 9.19615 \dots

Solution steps

3 (x + 4)^{2} - 81 = 0

Move

81

to the right side

3 (x + 4)^{2} = 81

Divide both sides by

3

(x + 4)^{2} = 27

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 27 : x = 33 - 4

Solve

x + 4 = - 27 : x = - 33 - 4

The solutions to the quadratic equation are:

x = 33 - 4, x = - 33 - 4

5 r^{2} - 10 r = 0

24 x^{2} - 12 x = 36 x

x^{2} - x - 180 = 0

2 z^{2} - 5 z - 2 = 2 z

35 x^{2} + 94 x + 24 = 0

What are the solutions to the equation 3(x+4)^2-81=0 ?
The solutions to the equation 3(x+4)^2-81=0 are x=3sqrt(3)-4,x=-3sqrt(3)-4
Find the zeros of 3(x+4)^2-81=0
The zeros of 3(x+4)^2-81=0 are x=3sqrt(3)-4,x=-3sqrt(3)-4