What are the solutions to the equation solvefor x,x^2-14x+35=-10 ?

The solutions to the equation solvefor x,x^2-14x+35=-10 are x=9,x=5

Find the zeros of solvefor x,x^2-14x+35=-10

The zeros of solvefor x,x^2-14x+35=-10 are x=9,x=5

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x, x^{2} - 14 x + 35 = - 10

x = 9, x = 5

Solution steps

x^{2} - 14 x + 35 = - 10

Move

10

to the left side

x^{2} - 14 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 45}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 45 = 4

x_{1, 2} = \frac{- ( - 14 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 4}{2 \cdot 1}

x = \frac{- ( - 14 ) + 4}{2 \cdot 1} : 9

x = \frac{- ( - 14 ) - 4}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

x = 9, x = 5

2 \cdot (x + 4)^{2} = x^{2} - 13

3 a^{2} + 4 a - 5 = 0

- 3 x^{2} + 2 x + 3 = 0

b (w) = 4 w^{2} + 5 w + 100

\frac{x ^{2}}{16} = 1

What are the solutions to the equation solvefor x,x^2-14x+35=-10 ?
The solutions to the equation solvefor x,x^2-14x+35=-10 are x=9,x=5
Find the zeros of solvefor x,x^2-14x+35=-10
The zeros of solvefor x,x^2-14x+35=-10 are x=9,x=5