What are the solutions to the equation 3r^2-6r=13 ?

The solutions to the equation 3r^2-6r=13 are r=(3+4sqrt(3))/3 ,r=(3-4sqrt(3))/3

Find the zeros of 3r^2-6r=13

The zeros of 3r^2-6r=13 are r=(3+4sqrt(3))/3 ,r=(3-4sqrt(3))/3

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3 r^{2} - 6 r = 13

r = \frac{3 + 4 3}{3}, r = \frac{3 - 4 3}{3}

Decimal Notation

r = 3.30940 \dots, r = - 1.30940 \dots

Solution steps

3 r^{2} - 6 r = 13

Move

13

to the left side

3 r^{2} - 6 r - 13 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 13 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 13) = 83

r_{1, 2} = \frac{- ( - 6 ) \pm 8 3}{2 \cdot 3}

Separate the solutions

r_{1} = \frac{- ( - 6 ) + 8 3}{2 \cdot 3}, r_{2} = \frac{- ( - 6 ) - 8 3}{2 \cdot 3}

r = \frac{- ( - 6 ) + 8 3}{2 \cdot 3} : \frac{3 + 4 3}{3}

r = \frac{- ( - 6 ) - 8 3}{2 \cdot 3} : \frac{3 - 4 3}{3}

The solutions to the quadratic equation are:

r = \frac{3 + 4 3}{3}, r = \frac{3 - 4 3}{3}

16 v^{2} - 4 = 12

4 - 6 (2 x + 1) = 10

x, 3 x = 6 + 2 y

10 x + 2 x + 3 (x - 8) - 30 = 0

5 + 14 x = 9 x - 5

What are the solutions to the equation 3r^2-6r=13 ?
The solutions to the equation 3r^2-6r=13 are r=(3+4sqrt(3))/3 ,r=(3-4sqrt(3))/3
Find the zeros of 3r^2-6r=13
The zeros of 3r^2-6r=13 are r=(3+4sqrt(3))/3 ,r=(3-4sqrt(3))/3