What are the solutions to the equation x^2-8x=9 ?

The solutions to the equation x^2-8x=9 are x=9,x=-1

Find the zeros of x^2-8x=9

The zeros of x^2-8x=9 are x=9,x=-1

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x^{2} - 8 x = 9

x = 9, x = - 1

Solution steps

x^{2} - 8 x = 9

Move

9

to the left side

x^{2} - 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 9) = 10

x_{1, 2} = \frac{- ( - 8 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 10}{2 \cdot 1}

x = \frac{- ( - 8 ) + 10}{2 \cdot 1} : 9

x = \frac{- ( - 8 ) - 10}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 9, x = - 1

(53 + 15) \cdot (35 - 15)

- 5 x^{4} + 5 > 0

\frac{r ^{3} v ^{- 2}}{t ^{- 7}}

(- \frac{5}{7}) (- \frac{21}{10})

4 x^{2} + x = 3

What are the solutions to the equation x^2-8x=9 ?
The solutions to the equation x^2-8x=9 are x=9,x=-1
Find the zeros of x^2-8x=9
The zeros of x^2-8x=9 are x=9,x=-1