What are the solutions to the equation -2(6w^2+7w-210)=0 ?

The solutions to the equation -2(6w^2+7w-210)=0 are w=-(7+sqrt(5089))/(12),w=(sqrt(5089)-7)/(12)

Find the zeros of -2(6w^2+7w-210)=0

The zeros of -2(6w^2+7w-210)=0 are w=-(7+sqrt(5089))/(12),w=(sqrt(5089)-7)/(12)

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- 2 (6 w^{2} + 7 w - 210) = 0

w = - \frac{7 + 5089}{12}, w = \frac{5089 - 7}{12}

Decimal Notation

w = - 6.52810 \dots, w = 5.36143 \dots

Solution steps

- 2 (6 w^{2} + 7 w - 210) = 0

Expand

- 2 (6 w^{2} + 7 w - 210) : - 12 w^{2} - 14 w + 420

- 12 w^{2} - 14 w + 420 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 ( - 12 ) \cdot 420}{2 ( - 12 )}

(- 14)^{2} - 4 (- 12) \cdot 420 = 25089

w_{1, 2} = \frac{- ( - 14 ) \pm 2 5089}{2 ( - 12 )}

Separate the solutions

w_{1} = \frac{- ( - 14 ) + 2 5089}{2 ( - 12 )}, w_{2} = \frac{- ( - 14 ) - 2 5089}{2 ( - 12 )}

w = \frac{- ( - 14 ) + 2 5089}{2 ( - 12 )} : - \frac{7 + 5089}{12}

w = \frac{- ( - 14 ) - 2 5089}{2 ( - 12 )} : \frac{5089 - 7}{12}

The solutions to the quadratic equation are:

w = - \frac{7 + 5089}{12}, w = \frac{5089 - 7}{12}

\frac{( x - 15 )}{15} + \frac{x}{5} - 1 = 0

12 x^{2} + 7 x - 10

\frac{( x - 1 )}{x - 13} < 0

4 x^{2} + 3 x + 8 = 0

6 x^{2} - 13 x + 6 = 0

What are the solutions to the equation -2(6w^2+7w-210)=0 ?
The solutions to the equation -2(6w^2+7w-210)=0 are w=-(7+sqrt(5089))/(12),w=(sqrt(5089)-7)/(12)
Find the zeros of -2(6w^2+7w-210)=0
The zeros of -2(6w^2+7w-210)=0 are w=-(7+sqrt(5089))/(12),w=(sqrt(5089)-7)/(12)