What is the answer to (7x-3)/3 =(3x-4)/8 ?

The answer to (7x-3)/3 =(3x-4)/8 is x= 12/47

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(7x-3)/3 =(3x-4)/8

\frac{7 x - 3}{3} = \frac{3 x - 4}{8}

x = \frac{12}{47}

Solution steps

\frac{7 x - 3}{3} = \frac{3 x - 4}{8}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(7 x - 3) \cdot 8 = 3 (3 x - 4)

Expand

(7 x - 3) \cdot 8 : 56 x - 24

Expand

3 (3 x - 4) : 9 x - 12

56 x - 24 = 9 x - 12

Move

24

to the right side

56 x = 9 x + 12

Move

9 x

to the left side

47 x = 12

Divide both sides by

47

x = \frac{12}{47}

x, y^{3} = 3 B x

\frac{y}{3} = - 6

\frac{3}{5} f + 24 = 4 - \frac{1}{5} f

- 6 (- 3 x - 1) + 2 = 8 x + 7

n - 1.4 = - 6.3

What is the answer to (7x-3)/3 =(3x-4)/8 ?
The answer to (7x-3)/3 =(3x-4)/8 is x= 12/47
Solve for x: (7x-3)/3 =(3x-4)/8
The solution is x= 12/47