What is the answer to solvefor h,s=2pir^2+2pirh ?

The answer to solvefor h,s=2pir^2+2pirh is h=(s-2pir^2)/(2pir);\quad r\ne 0

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solvefor h,s=2pir^2+2pirh

solve for

h, s = 2 π r^{2} + 2 π r h

h = \frac{s - 2 π r ^{2}}{2 π r}; r \neq = 0

Solution steps

s = 2 π r^{2} + 2 π r h

Switch sides

2 π r^{2} + 2 π r h = s

Move

2 π r^{2}

to the right side

2 π r h = s - 2 π r^{2}

Divide both sides by

2 π r; r \neq = 0

h = \frac{s - 2 π r ^{2}}{2 π r}; r \neq = 0

29 = 1 + \frac{1}{2} x

8 (5 x - 3) = 6 (- 3 x - 4)

\frac{2}{11} x + 3 = 11

\frac{m}{10} + 15 = 21

- 4 (2 n - 5) = - 28

What is the answer to solvefor h,s=2pir^2+2pirh ?
The answer to solvefor h,s=2pir^2+2pirh is h=(s-2pir^2)/(2pir);\quad r\ne 0