What is the answer to solvefor x,y=f(x-3)+2 ?

The answer to solvefor x,y=f(x-3)+2 is x=(y-2)/f+3;\quad f\ne 0

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solvefor x,y=f(x-3)+2

solve for

x, y = f (x - 3) + 2

x = \frac{y - 2}{f} + 3; f \neq = 0

Solution steps

y = f (x - 3) + 2

Switch sides

f (x - 3) + 2 = y

Move

2

to the right side

f (x - 3) = y - 2

Divide both sides by

f; f \neq = 0

x - 3 = \frac{y - 2}{f}; f \neq = 0

Move

3

to the right side

x = \frac{y - 2}{f} + 3; f \neq = 0

9 = - \frac{7}{10} a - 12

\frac{5 r}{2} - 6 = 19

r, r - rs = 2 rs + 5

3 x - 8 (2 x + 3) = - 6 (2 x + 5)

20 + \frac{2}{9} a = 38

What is the answer to solvefor x,y=f(x-3)+2 ?
The answer to solvefor x,y=f(x-3)+2 is x=(y-2)/f+3;\quad f\ne 0