What are the solutions to the equation y^2+5y-14=0 ?

The solutions to the equation y^2+5y-14=0 are y=2,y=-7

Find the zeros of y^2+5y-14=0

The zeros of y^2+5y-14=0 are y=2,y=-7

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y^{2} + 5 y - 14 = 0

y = 2, y = - 7

Solution steps

y^{2} + 5 y - 14 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 14) = 9

y_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 5 + 9}{2 \cdot 1}, y_{2} = \frac{- 5 - 9}{2 \cdot 1}

y = \frac{- 5 + 9}{2 \cdot 1} : 2

y = \frac{- 5 - 9}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

y = 2, y = - 7

(x - 3) (x + 1) \geq 0

24 < 5 x - 1

- - 12

0.1 (30) + 8 - 12 (\frac{1}{4})

666

What are the solutions to the equation y^2+5y-14=0 ?
The solutions to the equation y^2+5y-14=0 are y=2,y=-7
Find the zeros of y^2+5y-14=0
The zeros of y^2+5y-14=0 are y=2,y=-7