What is the answer to 9(q+8)-(3q-5)=21+11(-2q-13) ?

The answer to 9(q+8)-(3q-5)=21+11(-2q-13) is q=-199/28

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9(q+8)-(3q-5)=21+11(-2q-13)

9 (q + 8) - (3 q - 5) = 21 + 11 (- 2 q - 13)

q = - \frac{199}{28}

Decimal Notation

q = - 7.10714 \dots

Solution steps

9 (q + 8) - (3 q - 5) = 21 + 11 (- 2 q - 13)

Expand

9 (q + 8) - (3 q - 5) : 6 q + 77

Expand

21 + 11 (- 2 q - 13) : - 22 q - 122

6 q + 77 = - 22 q - 122

Move

77

to the right side

6 q = - 22 q - 199

Move

22 q

to the left side

28 q = - 199

Divide both sides by

28

q = - \frac{199}{28}

4.7 x 1 0^{- 3} = 4.7 x \frac{1}{1000}

6 (4 s + 12) = 8 (3 s - 14)

\frac{b}{3 + 17} = 48

7 - 3 z - 4 z = 28

5 c - 7 = 8 c - 4

What is the answer to 9(q+8)-(3q-5)=21+11(-2q-13) ?
The answer to 9(q+8)-(3q-5)=21+11(-2q-13) is q=-199/28
Solve for q: 9(q+8)-(3q-5)=21+11(-2q-13)
The solution is q=-199/28