What is ((x+3)(2x-6))/(x^2)>0 ?

The solution to ((x+3)(2x-6))/(x^2)>0 is x 3

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((x+3)(2x-6))/(x^2)>0

\frac{( x + 3 ) ( 2 x - 6 )}{x ^{2}} > 0

x < - 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (3, \infty)

Solution steps

\frac{( x + 3 ) ( 2 x - 6 )}{x ^{2}} > 0

Factor

\frac{( x + 3 ) ( 2 x - 6 )}{x ^{2}} : \frac{2 ( x + 3 ) ( x - 3 )}{x ^{2}}

\frac{2 ( x + 3 ) ( x - 3 )}{x ^{2}} > 0

Divide both sides by

2

\frac{\frac{2 ( x + 3 ) ( x - 3 )}{x ^{2}}}{2} > \frac{0}{2}

Simplify

\frac{( x + 3 ) ( x - 3 )}{x ^{2}} > 0

Identify the intervals

x < - 3 or x > 3

- \frac{9}{4} z - (\frac{3}{4} - \frac{5}{4} z) = 0

3 x - x + 4 = 4 (2 x - 1)

\frac{4}{3 x + 1} \leq \frac{2}{x - 4}

\frac{- 6}{i}

What is ((x+3)(2x-6))/(x^2)>0 ?
The solution to ((x+3)(2x-6))/(x^2)>0 is x<-3\lor x>3