What is the answer to solvefor x,3y-2xy-3y^2=0 ?

The answer to solvefor x,3y-2xy-3y^2=0 is x=-(3(y-1))/2 ;\quad y\ne 0

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solvefor x,3y-2xy-3y^2=0

solve for

x, 3 y - 2 x y - 3 y^{2} = 0

x = - \frac{3 ( y - 1 )}{2}; y \neq = 0

Solution steps

3 y - 2 x y - 3 y^{2} = 0

Move

3 y

to the right side

- 2 x y - 3 y^{2} = - 3 y

Move

3 y^{2}

to the right side

- 2 x y = - 3 y + 3 y^{2}

Divide both sides by

- 2 y; y \neq = 0

x = - \frac{3 ( y - 1 )}{2}; y \neq = 0

x, 12 (m + 3 x) = 18 (x - 3 m)

\frac{4}{3} t = - 2

x, e^{- 2} x - y = 5

0.7 + y = - 1.34

3 (x - 2) = 6 (5 + x)

What is the answer to solvefor x,3y-2xy-3y^2=0 ?
The answer to solvefor x,3y-2xy-3y^2=0 is x=-(3(y-1))/2 ;\quad y\ne 0