What is the answer to (4x-3)(2x+3)-8x(x-4)=0 ?

The answer to (4x-3)(2x+3)-8x(x-4)=0 is x= 9/38

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(4x-3)(2x+3)-8x(x-4)=0

(4 x - 3) (2 x + 3) - 8 x (x - 4) = 0

x = \frac{9}{38}

Solution steps

(4 x - 3) (2 x + 3) - 8 x (x - 4) = 0

Expand

(4 x - 3) (2 x + 3) - 8 x (x - 4) : 38 x - 9

38 x - 9 = 0

Move

9

to the right side

38 x = 9

Divide both sides by

38

x = \frac{9}{38}

a, x + a = y

4 - 6 (2 x - 1) = 10

- 98 + 2 (18 g + 11) = 40 g

- 4 (3 m - 10) - 6 (- 7 m - 6) = - 74

3 (x - 2) - 2 (x + 7) = 2 x + 17

What is the answer to (4x-3)(2x+3)-8x(x-4)=0 ?
The answer to (4x-3)(2x+3)-8x(x-4)=0 is x= 9/38
Solve for x: (4x-3)(2x+3)-8x(x-4)=0
The solution is x= 9/38