What are the solutions to the equation 2x^2+5x-10=0 ?

The solutions to the equation 2x^2+5x-10=0 are x=(-5+sqrt(105))/4 ,x=(-5-sqrt(105))/4

Find the zeros of 2x^2+5x-10=0

The zeros of 2x^2+5x-10=0 are x=(-5+sqrt(105))/4 ,x=(-5-sqrt(105))/4

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2 x^{2} + 5 x - 10 = 0

x = \frac{- 5 + 105}{4}, x = \frac{- 5 - 105}{4}

Decimal Notation

x = 1.31173 \dots, x = - 3.81173 \dots

Solution steps

2 x^{2} + 5 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 10) = 105

x_{1, 2} = \frac{- 5 \pm 105}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 105}{2 \cdot 2}, x_{2} = \frac{- 5 - 105}{2 \cdot 2}

x = \frac{- 5 + 105}{2 \cdot 2} : \frac{- 5 + 105}{4}

x = \frac{- 5 - 105}{2 \cdot 2} : \frac{- 5 - 105}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 105}{4}, x = \frac{- 5 - 105}{4}

(2 + 8 i) - (- 5 - 3 i)

4 x^{3} y - 2 y^{2} x^{3}

5 x - 7 (- x + 2) = 58

- \frac{40}{( 4 ( 4 ) - 5 ) ^{2}}

16 k^{2} - 1

What are the solutions to the equation 2x^2+5x-10=0 ?
The solutions to the equation 2x^2+5x-10=0 are x=(-5+sqrt(105))/4 ,x=(-5-sqrt(105))/4
Find the zeros of 2x^2+5x-10=0
The zeros of 2x^2+5x-10=0 are x=(-5+sqrt(105))/4 ,x=(-5-sqrt(105))/4