What is the answer to (x+1)^2+2(x-2)=(x+1)(x-2) ?

The answer to (x+1)^2+2(x-2)=(x+1)(x-2) is x= 1/5

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(x+1)^2+2(x-2)=(x+1)(x-2)

(x + 1)^{2} + 2 (x - 2) = (x + 1) (x - 2)

x = \frac{1}{5}

Decimal Notation

x = 0.2

Solution steps

(x + 1)^{2} + 2 (x - 2) = (x + 1) (x - 2)

Expand

(x + 1)^{2} + 2 (x - 2) : x^{2} + 4 x - 3

Expand

(x + 1) (x - 2) : x^{2} - x - 2

x^{2} + 4 x - 3 = x^{2} - x - 2

Move

3

to the right side

x^{2} + 4 x = x^{2} - x + 1

Subtract

x^{2} - x

from both sides

x^{2} + 4 x - (x^{2} - x) = x^{2} - x + 1 - (x^{2} - x)

Simplify

5 x = 1

Divide both sides by

5

x = \frac{1}{5}

- 5 x + 1 - 3 (x + 2) = - 9 x + 15

- 9 = - \frac{2}{3} s

\frac{x}{4} = \frac{5}{7}

x, x + y - 2 z = 5

14 - (x + 1) = 2 x - 2

What is the answer to (x+1)^2+2(x-2)=(x+1)(x-2) ?
The answer to (x+1)^2+2(x-2)=(x+1)(x-2) is x= 1/5
Solve for x: (x+1)^2+2(x-2)=(x+1)(x-2)
The solution is x= 1/5