What is the answer to solvefor v,h=vt-5t^2 ?

The answer to solvefor v,h=vt-5t^2 is v=(h+5t^2)/t ;\quad t\ne 0

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solvefor v,h=vt-5t^2

solve for

v, h = v t - 5 t^{2}

v = \frac{h + 5 t ^{2}}{t}; t \neq = 0

Solution steps

h = v t - 5 t^{2}

Switch sides

v t - 5 t^{2} = h

Move

5 t^{2}

to the right side

v t = h + 5 t^{2}

Divide both sides by

t; t \neq = 0

v = \frac{h + 5 t ^{2}}{t}; t \neq = 0

x - 3 (5 x - 3) = - 2

3 x + 6 + 9 x = - 33

\frac{w}{6} = - 8

6 = \frac{4}{3} y

9 (k - 2) = 3 (k + 4)

What is the answer to solvefor v,h=vt-5t^2 ?
The answer to solvefor v,h=vt-5t^2 is v=(h+5t^2)/t ;\quad t\ne 0