What are the solutions to the equation x^2+6x-19=0 ?

The solutions to the equation x^2+6x-19=0 are x=-3+2sqrt(7),x=-3-2sqrt(7)

Find the zeros of x^2+6x-19=0

The zeros of x^2+6x-19=0 are x=-3+2sqrt(7),x=-3-2sqrt(7)

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x^{2} + 6 x - 19 = 0

x = - 3 + 27, x = - 3 - 27

Decimal Notation

x = 2.29150 \dots, x = - 8.29150 \dots

Solution steps

x^{2} + 6 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 19 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 19) = 47

x_{1, 2} = \frac{- 6 \pm 4 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4 7}{2 \cdot 1}, x_{2} = \frac{- 6 - 4 7}{2 \cdot 1}

x = \frac{- 6 + 4 7}{2 \cdot 1} : - 3 + 27

x = \frac{- 6 - 4 7}{2 \cdot 1} : - 3 - 27

The solutions to the quadratic equation are:

x = - 3 + 27, x = - 3 - 27

a^{3}

x + 7 > 4

8 \times 6

\frac{4}{2 - 3 i}

9 (x + 1) = 4 - 2 (9 x + 5)

What are the solutions to the equation x^2+6x-19=0 ?
The solutions to the equation x^2+6x-19=0 are x=-3+2sqrt(7),x=-3-2sqrt(7)
Find the zeros of x^2+6x-19=0
The zeros of x^2+6x-19=0 are x=-3+2sqrt(7),x=-3-2sqrt(7)