What is the answer to solvefor A,q^2=g(-h+A) ?

The answer to solvefor A,q^2=g(-h+A) is A=(q^2)/g+h;\quad g\ne 0

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solvefor A,q^2=g(-h+A)

solve for

A, q^{2} = g (- h + A)

A = \frac{q ^{2}}{g} + h; g \neq = 0

Solution steps

q^{2} = g (- h + A)

Switch sides

g (- h + A) = q^{2}

Divide both sides by

g; g \neq = 0

- h + A = \frac{q ^{2}}{g}; g \neq = 0

Move

h

to the right side

A = \frac{q ^{2}}{g} + h; g \neq = 0

2 (x - 5) + 3 (x + 5) = 20

y - 7 = 8

9 + 5 w - 14 w = 12 - 6 w

f = - 2 - (- 2) \cdot 3 + 3^{2}

3.8 - \frac{x}{2.5} = 4.16

What is the answer to solvefor A,q^2=g(-h+A) ?
The answer to solvefor A,q^2=g(-h+A) is A=(q^2)/g+h;\quad g\ne 0