What are the solutions to the equation 6x^2+12x+63=0 ?

The solutions to the equation 6x^2+12x+63=0 are x=-1+isqrt(19/2),x=-1-isqrt(19/2)

Find the zeros of 6x^2+12x+63=0

The zeros of 6x^2+12x+63=0 are x=-1+isqrt(19/2),x=-1-isqrt(19/2)

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6 x^{2} + 12 x + 63 = 0

x = - 1 + i \frac{19}{2}, x = - 1 - i \frac{19}{2}

Solution steps

6 x^{2} + 12 x + 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 6 \cdot 63}{2 \cdot 6}

Simplify

1 2^{2} - 4 \cdot 6 \cdot 63 : 638 i

x_{1, 2} = \frac{- 12 \pm 6 38 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 12 + 6 38 i}{2 \cdot 6}, x_{2} = \frac{- 12 - 6 38 i}{2 \cdot 6}

x = \frac{- 12 + 6 38 i}{2 \cdot 6} : - 1 + i \frac{19}{2}

x = \frac{- 12 - 6 38 i}{2 \cdot 6} : - 1 - i \frac{19}{2}

The solutions to the quadratic equation are:

x = - 1 + i \frac{19}{2}, x = - 1 - i \frac{19}{2}

5 lo g_{4} (x) + 3 lo g_{4} (y)

5 - 6

- 16 x^{2} + 16 x + 5 \geq 0

9 = 0

\frac{83}{4} = 83 \cdot x

What are the solutions to the equation 6x^2+12x+63=0 ?
The solutions to the equation 6x^2+12x+63=0 are x=-1+isqrt(19/2),x=-1-isqrt(19/2)
Find the zeros of 6x^2+12x+63=0
The zeros of 6x^2+12x+63=0 are x=-1+isqrt(19/2),x=-1-isqrt(19/2)