What is the answer to 9+3b+2(b-1)=67 ?

The answer to 9+3b+2(b-1)=67 is b=12

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9+3b+2(b-1)=67

9 + 3 b + 2 (b - 1) = 67

b = 12

Solution steps

9 + 3 b + 2 (b - 1) = 67

Move

9

to the right side

3 b + 2 (b - 1) = 58

Expand

2 (b - 1) : 2 b - 2

3 b + 2 b - 2 = 58

Add similar elements:

3 b + 2 b = 5 b

5 b - 2 = 58

Move

2

to the right side

5 b = 60

Divide both sides by

5

b = 12

- 1 + t = - 7

- 3 (33 b + 65) = - 95 b - 6 b - 87

8 = \frac{r}{5}

\frac{x}{4} + \frac{x}{3} = 2

2.5 x + 1 - 7 x = - 44