What are the solutions to the equation 4y^2=81 ?

The solutions to the equation 4y^2=81 are y= 9/2 ,y=-9/2

Find the zeros of 4y^2=81

The zeros of 4y^2=81 are y= 9/2 ,y=-9/2

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4 y^{2} = 81

y = \frac{9}{2}, y = - \frac{9}{2}

Solution steps

4 y^{2} = 81

Divide both sides by

4

y^{2} = \frac{81}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{81}{4}, y = - \frac{81}{4}

\frac{81}{4} = \frac{9}{2}

- \frac{81}{4} = - \frac{9}{2}

y = \frac{9}{2}, y = - \frac{9}{2}

- 6 x + 4 = - 20

\frac{2 π}{2}

- 6 x - 3 = 1 + 4 (x + 4)

45 = 5 t + 45

11

What are the solutions to the equation 4y^2=81 ?
The solutions to the equation 4y^2=81 are y= 9/2 ,y=-9/2
Find the zeros of 4y^2=81
The zeros of 4y^2=81 are y= 9/2 ,y=-9/2