What are the solutions to the equation x^2+6x-160=0 ?

The solutions to the equation x^2+6x-160=0 are x=10,x=-16

Find the zeros of x^2+6x-160=0

The zeros of x^2+6x-160=0 are x=10,x=-16

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x^{2} + 6 x - 160 = 0

x = 10, x = - 16

Solution steps

x^{2} + 6 x - 160 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 160 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 160) = 26

x_{1, 2} = \frac{- 6 \pm 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 26}{2 \cdot 1}, x_{2} = \frac{- 6 - 26}{2 \cdot 1}

x = \frac{- 6 + 26}{2 \cdot 1} : 10

x = \frac{- 6 - 26}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = 10, x = - 16

x^{2} = 2

1010

∣ 2 x - 4 ∣ > 10

3 x - 9 \geq - 21

(81 x^{- 32} y^{4})^{\frac{3}{4}}

What are the solutions to the equation x^2+6x-160=0 ?
The solutions to the equation x^2+6x-160=0 are x=10,x=-16
Find the zeros of x^2+6x-160=0
The zeros of x^2+6x-160=0 are x=10,x=-16