What are the solutions to the equation 5w^2=26w+24 ?

The solutions to the equation 5w^2=26w+24 are w=6,w=-4/5

Find the zeros of 5w^2=26w+24

The zeros of 5w^2=26w+24 are w=6,w=-4/5

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5 w^{2} = 26 w + 24

w = 6, w = - \frac{4}{5}

Solution steps

5 w^{2} = 26 w + 24

Move

24

to the left side

5 w^{2} - 24 = 26 w

Move

26 w

to the left side

5 w^{2} - 24 - 26 w = 0

Write in the standard form

a x^{2} + b x + c = 0

5 w^{2} - 26 w - 24 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 5 ( - 24 )}{2 \cdot 5}

(- 26)^{2} - 4 \cdot 5 (- 24) = 34

w_{1, 2} = \frac{- ( - 26 ) \pm 34}{2 \cdot 5}

Separate the solutions

w_{1} = \frac{- ( - 26 ) + 34}{2 \cdot 5}, w_{2} = \frac{- ( - 26 ) - 34}{2 \cdot 5}

w = \frac{- ( - 26 ) + 34}{2 \cdot 5} : 6

w = \frac{- ( - 26 ) - 34}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

w = 6, w = - \frac{4}{5}

e^{t} \cdot e^{t}

3 x^{2} - 12 x - 15

\frac{3}{3} + \frac{1}{3}

5 (x + 6) - 3 + 3 (x + 6) - 2

What are the solutions to the equation 5w^2=26w+24 ?
The solutions to the equation 5w^2=26w+24 are w=6,w=-4/5
Find the zeros of 5w^2=26w+24
The zeros of 5w^2=26w+24 are w=6,w=-4/5