What are the solutions to the equation 3z^2-8z+2=0 ?

The solutions to the equation 3z^2-8z+2=0 are z=(4+sqrt(10))/3 ,z=(4-sqrt(10))/3

Find the zeros of 3z^2-8z+2=0

The zeros of 3z^2-8z+2=0 are z=(4+sqrt(10))/3 ,z=(4-sqrt(10))/3

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3 z^{2} - 8 z + 2 = 0

z = \frac{4 + 10}{3}, z = \frac{4 - 10}{3}

Solution steps

3 z^{2} - 8 z + 2 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 \cdot 2 = 210

z_{1, 2} = \frac{- ( - 8 ) \pm 2 10}{2 \cdot 3}

Separate the solutions

z_{1} = \frac{- ( - 8 ) + 2 10}{2 \cdot 3}, z_{2} = \frac{- ( - 8 ) - 2 10}{2 \cdot 3}

z = \frac{- ( - 8 ) + 2 10}{2 \cdot 3} : \frac{4 + 10}{3}

z = \frac{- ( - 8 ) - 2 10}{2 \cdot 3} : \frac{4 - 10}{3}

The solutions to the quadratic equation are:

z = \frac{4 + 10}{3}, z = \frac{4 - 10}{3}

n^{4} + 8 n^{2} + 15

(x - 1)^{\frac{1}{3}} - (x^{2} - x) (x - 1)^{- \frac{2}{3}}

e^{3 l n (3)}

(2 t)^{\frac{3}{2}}

1 x - 13 = 10

What are the solutions to the equation 3z^2-8z+2=0 ?
The solutions to the equation 3z^2-8z+2=0 are z=(4+sqrt(10))/3 ,z=(4-sqrt(10))/3
Find the zeros of 3z^2-8z+2=0
The zeros of 3z^2-8z+2=0 are z=(4+sqrt(10))/3 ,z=(4-sqrt(10))/3