What is factor 4a^2-28ab+49b^2 ?

The solution to factor 4a^2-28ab+49b^2 is (2a-7b)^2

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factor 4a^2-28ab+49b^2

factor

4 a^{2} - 28 ab + 49 b^{2}

(2 a - 7 b)^{2}

Solution steps

4 a^{2} - 28 ab + 49 b^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 a^{2} = (2 a)^{2}

49 b^{2} = (7 b)^{2}

- 28 ab = - 2 \cdot 2 a \cdot 7 b

= (2 a)^{2} - 2 \cdot 2 a \cdot 7 b + (7 b)^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(2 a)^{2} - 2 \cdot 2 a \cdot 7 b + (7 b)^{2} = (2 a - 7 b)^{2}

= (2 a - 7 b)^{2}

77 - 5175

4 x + 6 < 22

x^{5} y - x y^{4}

(x + 3) (x + 4) + y (x + 4)

- 10 p > 6 p - 8

What is factor 4a^2-28ab+49b^2 ?
The solution to factor 4a^2-28ab+49b^2 is (2a-7b)^2