What is the answer to solvefor x,f(x+1)=x-2 ?

The answer to solvefor x,f(x+1)=x-2 is x=(-2-f)/(f-1);\quad f\ne 1

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solvefor x,f(x+1)=x-2

solve for

x, f (x + 1) = x - 2

x = \frac{- 2 - f}{f - 1}; f \neq = 1

Solution steps

f (x + 1) = x - 2

Expand

f (x + 1) : x f + f

x f + f = x - 2

Move

f

to the right side

x f = x - 2 - f

Move

x

to the left side

x f - x = - 2 - f

Factor

x f - x : x (f - 1)

x (f - 1) = - 2 - f

Divide both sides by

f - 1; f \neq = 1

x = \frac{- 2 - f}{f - 1}; f \neq = 1

d, n d m - (m^{2} - 4) d n = 0

x, - 5 x + 2 y = 3 x + 24

0.45 (t + 8) = 0.6 (t - 3)

4 (3 x + 1) = 36

24 = - 6 r

What is the answer to solvefor x,f(x+1)=x-2 ?
The answer to solvefor x,f(x+1)=x-2 is x=(-2-f)/(f-1);\quad f\ne 1