What are the solutions to the equation 10s^2-24s-152=0 ?

The solutions to the equation 10s^2-24s-152=0 are s=(2(3+2sqrt(26)))/5 ,s=(2(3-2sqrt(26)))/5

Find the zeros of 10s^2-24s-152=0

The zeros of 10s^2-24s-152=0 are s=(2(3+2sqrt(26)))/5 ,s=(2(3-2sqrt(26)))/5

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10 s^{2} - 24 s - 152 = 0

s = \frac{2 ( 3 + 2 26 )}{5}, s = \frac{2 ( 3 - 2 26 )}{5}

Solution steps

10 s^{2} - 24 s - 152 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 10 ( - 152 )}{2 \cdot 10}

(- 24)^{2} - 4 \cdot 10 (- 152) = 1626

s_{1, 2} = \frac{- ( - 24 ) \pm 16 26}{2 \cdot 10}

Separate the solutions

s_{1} = \frac{- ( - 24 ) + 16 26}{2 \cdot 10}, s_{2} = \frac{- ( - 24 ) - 16 26}{2 \cdot 10}

s = \frac{- ( - 24 ) + 16 26}{2 \cdot 10} : \frac{2 ( 3 + 2 26 )}{5}

s = \frac{- ( - 24 ) - 16 26}{2 \cdot 10} : \frac{2 ( 3 - 2 26 )}{5}

The solutions to the quadratic equation are:

s = \frac{2 ( 3 + 2 26 )}{5}, s = \frac{2 ( 3 - 2 26 )}{5}

5 x - 18 \geq - 8

\frac{5}{2 5}

- \frac{1}{8} (x + 3)^{2} = 7

8 x + 38 = - 3 (- 6 - 4 x)

2 x^{2} + 4 x = 1

What are the solutions to the equation 10s^2-24s-152=0 ?
The solutions to the equation 10s^2-24s-152=0 are s=(2(3+2sqrt(26)))/5 ,s=(2(3-2sqrt(26)))/5
Find the zeros of 10s^2-24s-152=0
The zeros of 10s^2-24s-152=0 are s=(2(3+2sqrt(26)))/5 ,s=(2(3-2sqrt(26)))/5