What are the solutions to the equation p^2+14p-3=0 ?

The solutions to the equation p^2+14p-3=0 are p=-7+2sqrt(13),p=-7-2sqrt(13)

Find the zeros of p^2+14p-3=0

The zeros of p^2+14p-3=0 are p=-7+2sqrt(13),p=-7-2sqrt(13)

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p^{2} + 14 p - 3 = 0

p = - 7 + 213, p = - 7 - 213

Solution steps

p^{2} + 14 p - 3 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 3) = 413

p_{1, 2} = \frac{- 14 \pm 4 13}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 14 + 4 13}{2 \cdot 1}, p_{2} = \frac{- 14 - 4 13}{2 \cdot 1}

p = \frac{- 14 + 4 13}{2 \cdot 1} : - 7 + 213

p = \frac{- 14 - 4 13}{2 \cdot 1} : - 7 - 213

The solutions to the quadratic equation are:

p = - 7 + 213, p = - 7 - 213

- 3 (- 2)

- 4 x - 133 = 6 x + 147

4 x^{2} + 9 x + 3 = 0

\frac{1}{4 - 3}

8 x^{3} + 72 x^{2} + 160 x

What are the solutions to the equation p^2+14p-3=0 ?
The solutions to the equation p^2+14p-3=0 are p=-7+2sqrt(13),p=-7-2sqrt(13)
Find the zeros of p^2+14p-3=0
The zeros of p^2+14p-3=0 are p=-7+2sqrt(13),p=-7-2sqrt(13)