What are the solutions to the equation m^2+8m=-3 ?

The solutions to the equation m^2+8m=-3 are m=-4+sqrt(13),m=-4-sqrt(13)

Find the zeros of m^2+8m=-3

The zeros of m^2+8m=-3 are m=-4+sqrt(13),m=-4-sqrt(13)

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m^{2} + 8 m = - 3

m = - 4 + 13, m = - 4 - 13

Decimal Notation

m = - 0.39444 \dots, m = - 7.60555 \dots

Solution steps

m^{2} + 8 m = - 3

Move

3

to the left side

m^{2} + 8 m + 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 3 = 213

m_{1, 2} = \frac{- 8 \pm 2 13}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 8 + 2 13}{2 \cdot 1}, m_{2} = \frac{- 8 - 2 13}{2 \cdot 1}

m = \frac{- 8 + 2 13}{2 \cdot 1} : - 4 + 13

m = \frac{- 8 - 2 13}{2 \cdot 1} : - 4 - 13

The solutions to the quadratic equation are:

m = - 4 + 13, m = - 4 - 13

9 x^{2} + 10 x + 1 = 0

3 + \frac{2 + 7 x}{9} = 9

4 a^{2} - 8 a - 5

\frac{18 x ^{2} y}{2 y ^{3}}

f = - 2 (- 2) - 3

What are the solutions to the equation m^2+8m=-3 ?
The solutions to the equation m^2+8m=-3 are m=-4+sqrt(13),m=-4-sqrt(13)
Find the zeros of m^2+8m=-3
The zeros of m^2+8m=-3 are m=-4+sqrt(13),m=-4-sqrt(13)