What is the answer to 8x+2(x+1)=7(x-2)+3(x+1)+13 ?

The answer to 8x+2(x+1)=7(x-2)+3(x+1)+13 is True for all x

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8x+2(x+1)=7(x-2)+3(x+1)+13

8 x + 2 (x + 1) = 7 (x - 2) + 3 (x + 1) + 13

True for all x

Solution steps

8 x + 2 (x + 1) = 7 (x - 2) + 3 (x + 1) + 13

Expand

2 (x + 1) : 2 x + 2

8 x + 2 x + 2 = 7 (x - 2) + 3 (x + 1) + 13

Add similar elements:

8 x + 2 x = 10 x

10 x + 2 = 7 (x - 2) + 3 (x + 1) + 13

Expand

7 (x - 2) + 3 (x + 1) + 13 : 10 x + 2

10 x + 2 = 10 x + 2

Move

2

to the right side

10 x = 10 x

Move

10 x

to the left side

0 = 0

Both sides are equal

True for all x

8 x - 3 = 2 x + 57

9 = \frac{a}{10}

\frac{5 ( x - 3 ) + 4 x - 3}{3} = 8

4 x - 3 = 2 x + 9

5 x - 2 + 2 x + 6 = 67

What is the answer to 8x+2(x+1)=7(x-2)+3(x+1)+13 ?
The answer to 8x+2(x+1)=7(x-2)+3(x+1)+13 is True for all x
Solve for x: 8x+2(x+1)=7(x-2)+3(x+1)+13
The solution is True for all x