What is the answer to solvefor B,(B-4D^2)a=h ?

The answer to solvefor B,(B-4D^2)a=h is B= h/a+4D^2;\quad a\ne 0

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solvefor B,(B-4D^2)a=h

solve for

B, (B - 4 D^{2}) a = h

B = \frac{h}{a} + 4 D^{2}; a \neq = 0

Solution steps

(B - 4 D^{2}) a = h

Divide both sides by

a; a \neq = 0

B - 4 D^{2} = \frac{h}{a}; a \neq = 0

Move

4 D^{2}

to the right side

B = \frac{h}{a} + 4 D^{2}; a \neq = 0

2 x + 5 (- 3 x - 10) = - 154

4 x - 8 + 9 = 7 x + 18

- 15 + w = 6

\frac{x - 1}{3} + \frac{x + 1}{10} = 8

1 = \frac{v}{7} - 2

What is the answer to solvefor B,(B-4D^2)a=h ?
The answer to solvefor B,(B-4D^2)a=h is B= h/a+4D^2;\quad a\ne 0