What are the solutions to the equation x^2+0x+2=0 ?

The solutions to the equation x^2+0x+2=0 are x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of x^2+0x+2=0

The zeros of x^2+0x+2=0 are x=sqrt(2)i,x=-sqrt(2)i

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x^{2} + 0 x + 2 = 0

x = 2 i, x = - 2 i

Solution steps

x^{2} + 0 \cdot x + 2 = 0

Refine

x^{2} + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

0^{2} - 4 \cdot 1 \cdot 2 : 22 i

x_{1, 2} = \frac{- 0 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- 0 - 2 2 i}{2 \cdot 1}

x = \frac{- 0 + 2 2 i}{2 \cdot 1} : 2 i

x = \frac{- 0 - 2 2 i}{2 \cdot 1} : - 2 i

The solutions to the quadratic equation are:

x = 2 i, x = - 2 i

\frac{2}{3} x = 4

(x + 1) (x - 3) = 5

7 m^{2} - 8 mn + n^{2}

(5^{3})^{\frac{7}{6}}

5 y = 9 y^{2} - 4

What are the solutions to the equation x^2+0x+2=0 ?
The solutions to the equation x^2+0x+2=0 are x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of x^2+0x+2=0
The zeros of x^2+0x+2=0 are x=sqrt(2)i,x=-sqrt(2)i